9x^2-9/16=0

Solution for 9x^2-9/16=0 equation:

9x^2-9/16=0

We multiply all the terms by the denominator


9x^2*16-9=0

Wy multiply elements

144x^2-9=0

a = 144; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·144·(-9)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*144}=\frac{-72}{288}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*144}=\frac{72}{288}
=1/4
$